∴AB 1 = 1+ 1 = 2,
∴s△ab 1 c = 1 2× 1× 1 = 1 2;
∫Rt△AB 1 B2,B 1 B 2 = 1,AB 1 = 2+ 1 = 3,
∴ S △AB 1 B 2 = 2 2
…
∴ after the nth change, the right-angle side is always the same, and the length is1; The other right angle becomes n+ 1,
∴ The ratio of the area of the (n+ 1) th triangle to the area of the nth triangle is N2N+ 1.2, that is, N2N+ 1.
So the answer is: n n+ 1