(1) According to the end of the nth year, the deposit in the first year becomes A1(1+p) n-1,and the deposit in the second year becomes a2( 1+p)n-2, ..., which shows that W65438.

(2)W 1=a 1, Wn=Wn- 1( 1+p)+an, and reuse the above relationship for n≥2.

wn = wn- 1( 1+p)+an =[wn-2( 1+p)+an- 1]( 1+p)+an = wn-2(65438+。

…= w 1( 1+p)n- 1+a2( 1+p)n-2+…+an- 1( 1+p)+anwn = a 65438。

( 1+p)Wn = a 1( 1+p)n+a2( 1+p)n- 1+…+an- 1( 1+p)2+an( 1+p)②

②-①pWn = a 1( 1+p)n+d( 1+p)n- 1+d( 1+p)n-2…+d( 1+p)-an = DP[( 1+p)n？ 1? p]+a 1( 1+p)n？ Ann ... 8 ... 8 points

That is, wn = a 1p+dp2 (1+p) n? dpn？ a 1p+dp2

If an = a 1p+dp2 (1+p) n, bn =? dpn？ A 1p+dp2, … 10 point

Then TN = an+bn.

Where {An} is a geometric series with a 1p+dp2( 1+p) as the first term and (1+p) (p > 0) as the common ratio; {Bn} is based on? a 1p+dp2？ Dp is the first item. Dp is the tolerance of arithmetic series ... 14 points.