A, B, C, D and E are five elements with increasing atomic numbers. The outermost layer of element B has three more electrons than the inner layer, and the atom can only have two electron layers. If the number of electrons in the outermost layer is 5, then b is n element. If elements C and D belong to the same main family, and the number of atoms D is twice that of C, then C is element O and D is element S; Element e is located in group VIII of the fourth period, and its unpaired electrons in the ground state atoms are the same as those in the ground state carbon atoms. If the extranuclear electron configuration is 1s22s22p63s23p63d84s2, then E is Ni; From formula (4), element C and element A can form two common compounds, and their atomic number ratios are 1: 1 and 1: 2 respectively. Combined with the atomic number, we can know that element a is h,

The element (1)E is located in Group VIII of the fourth period, and the unpaired electrons in its ground state atoms are the same as those in its ground state carbon atoms. The extranuclear electron configuration is 1s22s22p63s23p63d84s2, and the electron configuration diagram of the ground state atom periphery is,

So the answer is:

(2) The 2p level of nitrogen contains three electrons, which is in a semi-complete stable state and has low energy. The first ionization energy is higher than oxygen, while O and S belong to the same main family. The first ionization energy decreases from top to bottom, and S.