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Party A and Party B go to the training center with a distance of 10km. L A and L B respectively indicate that Party A and Party B go to their destinations.
① B arrives at 28 o'clock and at 40 o'clock, so B arrives earlier than A 12 minutes; Therefore, ① is correct;

② According to the distance and time of A's arrival at the destination, the average speed of A is =10 ÷ 4060 =15 km/h; Therefore, 2 is correct;

(4) Assuming that B catches up with A after X minutes, there are:1028-18x =1040x (18x), and the solution is X = 6, so (4) is correct;

③ It can be seen from ④ that when B and A meet for the first time, the traveling distance is 6× 10 28- 18 =6km, so ③ is wrong;

So there are three correct conclusions: ① ② ④,

So choose B.

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