∠∠CBD =∠CAD+∠ACB,
∴∠CAD=30 =∠ACB,
∴AB=BC=20 nautical miles,
In Rt△CBD, ∠ BDC = 90, ∠ DBC = 60 and sin∠DBC=CDBC.
∴sin60 =CDBC,
∴ CD =12× sin60 = 20× 32 =103 nautical mile,
So the answer is: 103.