If the rope is not in smooth contact with the wheel, it will rotate and roll back when it is subjected to the rotating torque of the rope friction in the counterclockwise direction. If the contact is absolutely smooth, there will be no rotation and no rolling. These two situations have nothing to do with whether the ground is flat or not. If the force is constant, no matter how the included angle A changes, the distance from the shaft to the force (arm of force) is constant, so the rotational acceleration is constant, and the axial acceleration a=R*β, so it is a uniform acceleration linear motion. At this time, the rolling friction couple is not considered, so the angular acceleration β can be obtained by the formula M=J*β, and the pulling force is directly proportional to the acceleration.

When you put this picture vertically, it is a yo-yo, which explains why when you pull the rope for a certain length, the greater the downward throwing force, the greater the acceleration, and the approximate result of uniform acceleration shows that the final speed is large.

I hope it helps!