College chemistry questions! Don't enter if you don't understand! ! Questions marked with an asterisk! ! Please explain to the Great God! ! Thank you!

The electrode reaction of hydrogen electrode is 2H++2e- = H2(g).

The nernst equation is e = e (h+/h)+0.0592/2lg [c' (h+)/p' (H2)].

Therefore, the greater c(H+), the greater the potential of the conditional electrode.

However, due to the four conditions given in the title, c(H+) must be less than 1, and the potential value of the conditional electrode is negative. Therefore, it is necessary to choose the case where c(H+) is the minimum, and use this electrode as the negative electrode to obtain the maximum electromotive force (potential difference).

In the four cases given in the title, (a) is a strong acid, and c (h+) = c (HCl) = 0.1mol/L.

(b) As a buffer solution, the existence of a large amount of Ac- inhibits the dissociation of HAc, and the c(H+) in the solution is less than (c)0. 1mol/L HAc, and also less than (a).

(d) is a ternary weak acid, and c(H+) should be slightly greater than 0.1mol/l.

So this question should choose (b).

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