Here, we propose the derivation of a new set of equations, Lorentz transformation, and all the subordinate relations.
lorentz transformation
We consider the O coordinate system (reference system), one is the stationary S coordinate system, and the other is the coordinate system moving at a certain speed V relative to S, so according to the relativistic O postulate described in the text, the displacements in the two coordinate systems have the same form.
So, we have
(A- 1)
(A-2)
We should note that in the old galilean transformation, these equations were
(A-3)
This is in direct contradiction with hypothesis 2 (a conclusive experimental fact).
Equations (A- 1) and (A-2) can be written as follows
(A-4)
(A-5)
That is to say,
(A -6)
We are interested in finding x and t, that is,
= (x，t) (A-7)
= (x，t) (A-8)
This is achieved by forming the following linear simultaneous equations:
(A -9)
(A- 10)
Where a 1 1, a 12, a2 1 and a22 are constants to be calculated. The transformation is required to be linear in order to interpret an event in one system as an event in another system; Quadratic transformation means more than one event in another system.
Solving problems involving motion begins with the assumption of its initial conditions; That is, where does the problem begin?
The traditional assumption is to set = 0 when = 0. Therefore, for s, the system seems to be moving at speed v, so x = vt. We can get this from the equation. (A-9) Write it as = a 1 1(x-vt), so when = 0, x = vt. Therefore, we come to the conclusion that a 12 = -va 1 1. We can write equations (A-9) and (A- 10)
(A- 1 1)
(A- 12)
Substituting sum into equation (A-6) and rearranging it, we get
(A- 13)
Because this equation is equal to zero, all the coefficients must be zero. That is to say,
(A- 14)
(A- 15)
(A- 16)
By solving these equations, we get
(A- 17)
(A- 18)
Where β = v/c, and.
Therefore, these values are substituted into the equation. (A- 1 1) and (A- 12) We obtained the famous Lorentz coordinate transformation equation connecting the fixed coordinate system S to the moving coordinate system:
(A- 19)
(A-20)
We can also obtain the inverse transformation (from system to S) by replacing V with–V and simply exchanging the coordinates with and without apostrophe. This gives,
(A-2 1)
(A-22)
speed changing
As a direct result of these new transformations, all other mathematical operations and physical variables also follow. For example, the velocity equation (although still the derivative of displacement) has adopted a new form, so the Lorentz form of velocity is:
From Equas. (A- 19) and (A-20) we have:
(A -23)
(A -24)
Therefore:
(A -25)
Energy considerations
Suppose that a particle with a rest mass of m0 is acted by a force f with a distance of X in time t and reaches the final velocity v.. The kinetic energy obtained by a particle is defined as the work done by force F. The applicable equation is:
(A-26)
We noticed that
and
Substitute d(γv) into the equation. (45) and integral, we get
(A -27)
That is to say,
(A-28)
This means k = (m–m0) C2. Finally, we see that the total energy is equal to the sum of kiic energy k and residual energy E0 = m0c2.
That is, E = K+Eo = γm0c2 = γE0, (A-29)
Where E0 = m0c2 and E = mc2.
Give points.
The relativity of college physics E = E0/√ (1-1/4) = 2e0/√ 3.
W = e-E0 = E0 (2/√ 3-1) = 938 (2/√ 3-1) MeV.
The speed of solving the second universe in the relativity exercise of college physics is11.2km/s.
The relative mass formula is:
M=Mo/√( 1-v^2/c^2)
Mo is the mass of a stationary object, M is the mass of a moving object, V is the speed of the object, and C is the speed of light. It can be seen that the greater the speed, the greater the mass of the object. When an object moves at the speed of light, its mass is positive infinity.
You can substitute 1 1.2 into the formula to get the mass in motion, and subtract the original mass.
Remember to convert 100t into kg, 1t = 1000kg.
What a heavy blow! I hope you can understand!
It is a reality that college physics requires relativistic exercises. Every teacher thinks that he understands the theory of relativity correctly, but some teachers think that the theory of relativity is completely wrong. Some teachers think that there is something wrong with the theory of relativity and it needs to be revised; Although some teachers think that the theory of relativity is correct, they will give different answers to the same question.
So practice and ask the teacher for it. He will grade you and judge whether you are right or wrong.
Do you want to learn relativity in college physics? Both physics and applied physics should be studied, but not as a specialized subject, but as a part of a subject. Of course, in general universities, it is offered as an elective course for some majors, and some non-physics students can also learn "roughness" through elective courses. In fact, the physics major is also very shallow.
I advise you not to apply for the physics major, which is very promising unless you can get a master's degree or a higher level of study.
The formula of special relativity in college physics summarizes the work of Baidu Library.
College physics, special relativity, help, thank you. In fact, relativity is very easy to understand. For example, the relative velocity formula of the principle of constant light speed in special relativity is obtained through the geometric relationship of Michelson-Morey experiment, and the Lorentz coordinate transformation formula of relativity can be obtained through the differential transformation of the above formula. The rest of the length, time and mass can be obtained by skipping Lorentz transformation. I have a courseware of special relativity here. Please let me know if you need it.
The special theory of relativity in college physics? San ge Kao Dian
1, time relation
2. Length relation
3. Mass velocity formula, mass energy formula, relativistic kinetic energy (of course, you can divide it into three test sites).