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The distinction and calculation method of average kinetic energy and average translational kinetic energy in the theory of gas molecular motion in college physics. Thank you!
The average translational kinetic energy w of the ideal gas equation of state is 3kt/2, which is only related to temperature, so they are equal.

The average kinetic energy ω of molecules = average translational kinetic energy+average translational kinetic energy, which is related to the degree of freedom of molecules. The degree of freedom of monoatomic molecules is only i=3, and that of diatomic molecules is i=5, so the average kinetic energy of helium gas He=3kT/2 is not equal to that of helium gas O2=5KT/2.

So the answer is C.