h= 12gt2,
Have to? v=sg2h。
From the law of conservation of mechanical energy? EP= 12mv2=mgs24h
The expression of elastic potential energy of the spring before releasing the ball is Ep = mgs24h;;
(2) As can be seen from the data in the table, within the error range, S is directly proportional to X, that is, s=200x,
Ep=mgs24h, then the relationship between the elastic potential energy of the spring and the compression amount x of the spring should be? Ep= 104mgx2h
(3) According to Ep=mgs24h, the elastic potential energy of the compression spring before releasing the ball is Ep=mgL24y.
What should be the compression of the spring in step (II)? x=L200hy
(4) If the smooth horizontal groove is not perpendicular to the right edge of the table in the process of completing step (III), the small steel ball will throw obliquely downward, and Y will increase at this time, which is caused by
X = 1200hy indicates that the spring compression calculated by the method of (3) is less than the actual value.
So the answer is: (1)Ep=mgs24h.
(2)Ep= I praised it and stepped on it. What is your evaluation of this answer? Put away your comments and recommend lawyer services: If your problem is not solved, please describe your problem in detail and provide free professional consultation through Baidu Legal Pro. Other similar problems 2016-12-01A student designed an experiment to explore the relationship between elastic potential energy and compression of a spring according to the law of conservation of mechanical energy. (1) As shown in Figure (a), the lower end of the lightweight spring is112013-07-25. A student used the following device to explore the elastic potential energy of a lightweight spring: put the lightweight spring on a smooth horizontal table, with the left end of the spring fixed and the right end 1020 13-03-07. Experiments show that within the elastic limit of a spring, the original length of a spring is 10cm, and it hangs 5n102016-01-13. A student will study the relationship between the elastic potential energy of a light spring and the change of spring length. The experimental device is shown in Figure A. At the smooth level 120 16-04-08, a student will study the relationship between elastic potential energy of light spring and spring deformation. The experimental device is shown in the figure. A student will study the relationship between the elastic potential energy of light spring and the change of spring length on a smooth horizontal table with a height of h above the ground. His experiment is like this: on a smooth horizontal table with a height of h from the ground, 2016-05-11,a student uses the following device to explore the elastic potential energy of a light spring. A light spring is placed on a smooth horizontal desktop, and the left end of the spring is fixed. Right end 2014-11-27 A student uses the following device to explore the elastic potential energy of a light spring. A light spring is placed on a smooth horizontal desktop, and the left end of the spring is fixed, and the right end is 1 recommended to you: F.context('cmsRight', [{'URL':'/d01373f082025aaf511aa256a5. x-BCE-process = image % 2f resize % 2Cm _ lfit % 2Cw _ 450% 2Ch _ 600% 2c limit _ 1% 2f quality % 2Cq _ 85% 2f format % 2Cf _ auto ', ' contractId':'A24KA00562 ',},{ ' URL ':/builder/bjh-activity/articlesTask? taskId = 1598082 & aside = 0 & footer = true & from = 0 ',' src ':'/203 FB 80 e 7 bec 54 e 773 ea 0680 ab 389 b 504 fc 26 a2d? x-BCE-process = image % 2f resize % 2Cm _ lfit % 2Cw _ 450% 2Ch _ 600% 2c limit _ 1% 2f quality % 2Cq _ 85% 2f format % 2Cf _ auto ',' contractId ':' ',},{ ' URL ':/s? word = % E6 % AC % A7 % E6 % B4 % B2 % E6 % 9D % AF & sa = searchpromo _ ozb _ zhidao _ tuijian ',' src ':'/3 BF 33 a 87 e 950352 AAF 5 df 4954 143 fbf2b 2 1 18 b6b? x-BCE-process = image % 2f resize % 2Cm _ lfit % 2Cw _ 450% 2Ch _ 600% 2c limit _ 1% 2f quality % 2Cq _ 85% 2f format % 2Cf _ auto ',' contractId ':' ',}]); Why is the cost of cancer treatment getting higher and higher? What impact will the "network toilet" have? The price of electric cars has dropped many times. Is the quality guaranteed? Is Huaqiang North's second-hand mobile phone reliable? I recommend f.context ('recbrand', [{"img": "\/86D6277F9E2F07083523F69DFB 24B 899A901F20d? x-BCE-process = image % 2f resize % 2Cm _ lfit % 2Cw _ 450% 2Ch _ 600% 2c limit _ 1% 2f quality % 2Cq _ 85% 2f format % 2Cf _ auto "," url":"/hm.js? 6859 ce 5a af 00 FB 00387 e 6434 E4 FCC 925 "; var s = document . getelementsbytagname(" script ")[0]; s.parentNode.insertBefore(hm,s); })(); window . TT = 17209007 18;