The probability of a product can be regarded as a constant, that is, p (defective product) = 10%=0. 1.
The probability of getting qualified products every time is p (qualified) = 1-0. 1=0.9.
The probability of this batch of products passing the first inspection, that is, 10 pieces are all qualified, and the probability is
P 1=(P (qualified)) 10 = 0.9 10 = 0.349.
A: The probability of this batch of products passing the first inspection is 0.349.
2. Solution: The probability of secondary inspection is 1 or 2, and the probability is.
p2 = c( 10 1)0.9^9*0. 1+c( 10 2)*0.9^8*0. 1？ =0.58
A: The probability of the second test is 0.58.
3. Solution: The product is accepted according to the probability of the second inspection, that is, all the products are qualified after five times, then
P3=0.9^5=0.59
A: According to the second inspection, the probability of the product being accepted is 0.59.
4. Solution: This batch of products failed to make a decision in the first inspection, and the probability of passing the second inspection is
P4=P2*P3=0.58*0.59=0.34
A: It's 0.34.
5. Solution: The probability of this batch of products being accepted is divided by the probability of being accepted for the first time, that is, P 1 plus the probability of being accepted for the second time.
The probability of being admitted is P4, and the probability of being admitted is
P5=P 1+P4=0.349+0.34=0.69
A: The probability that this batch of products will be accepted is 0.69.
(Note: It refers to motivation.
For example, 2 3 is the cube of 2, and x n is the n power of x)