So the original formula is

ai *(n-& gt； Unlimited) lim [(a1/ai) n+(a2/ai) n+...+(an/ai) n] (1/n)

Because ai is the largest in a 1, a2...an, (A 1/AI) n = 0 or 1.

1≤(a 1/ai)^n+(a2/ai)^n+...+(an/ai)^n≤n

Using the grip criterion, we can know that

(n->； Unlimited) lim [(a1/ai) n+(a2/ai) n+...+(an/ai) n] (1/n) =1.

So the original formula =ai