From the uniqueness of the limit, we can see that there is no choice of C in the sub-limit.
2 original formula = ∫ (cost ∧ 2+Sint ∧ 2) * √ s (-int square+cost square) dt = ∫ dt, 2pi chooses c as the lower limit 0 and 2pi as the upper limit.
3 staggered series converges but its absolute value does not converge. Choose D.
4 attribute selection a
5 lim[x∧(n+ 1)/2(n+ 1)]/(x∧n/2n)& lt； 1
Get the absolute value of x
Partial derivative x =F 1+F2 * Y of large problem pair.
X before y derivative = f11+f12 * x+(f 21+f22 * x) * y+F2. It's not easy to write with a mobile phone!