The position of the number in this series is (10+ 1)/2=5.5, which is between 1 13 and the second 13. Because there are three identical values 13 near the middle position, the area should be regarded as an interval, that is, there are three 13( 12.5, 13.5) in the interval.
After dividing the interval, it is easy to get that the first interval corresponding to 13 and the second interval corresponding to 12.5,12.5+13 and (12.5+/kloc) respectively. The position of the median is between these two 13, and its value is the boundary value of the two intervals: 12.5+ 1/3.
The median of this series is 77/6 through differential simplification.