When x=3, the power series becomes ∑ 1/n and diverges.
When x=-3, the power series becomes ∑ 1 (- 1) n/n, and the series converges by Leibniz theorem.
So the convergence domain is [-3,3].
2、f(x)= 1/((x+ 1)(x+2))= 1/( 1+x)- 1/(2+x)= 1/( 1+x)- 1/2× 1/( 1+x/2)
1/( 1+x)=∑(- 1)^n*x^n,- 1