(1) angular velocity w=kt? , then w 1/w2=(t 1/t2)? ,

So the linear velocity is v1/v2 = w1/w2 = (t1/t2)? =( 1/2)? = 1/4

So the speed at t= 1s is v1= v2× (1/4) = 8m/s.

Wait for the next two questions and reply immediately.

(2) The tangential acceleration is a function V=kRt? Derive t,

So tangential acceleration a tangent =2t=2m? /s

(3) when t = 1s, the angular velocity of point p w = 2π× v/(2π r) = v/r = 4;

According to the question, w=kt? , so k=w/(t? )=4

Again, centripetal acceleration direction A =w? ×R=(kt？ )? ×R

So when t= 1s, the direction A =k? ×R=32m？ /m