The equation of motion is represented by a potential vector.

r=∫2tdt i +∫2dt j+c=t^2 i +2t j +c

When substituting t=0, r = j and c = j.

r=t^2 i +(2t+ 1) j

Synthetic acceleration vector a=dv/dt=2i.

The magnitude of the synthesized acceleration vector a=2.

Speed v = √ ((2t) 2+2 2) = 2 √ (t2+1)

at = dv/dt = d(2 √( T2+ 1)/dt = 2t/√( T2+ 1)。

Normal acceleration an = √ (A2-at 2) = √ (22-(2t/√ (T2+1)) 2)