Tangential acceleration a at t= 1s? = dv/dt =- 1.2t =- 1.2m/s？
Normal acceleration a at t= 1s? =v？ /R= 1.88m/s？
The acceleration at t= 1s is a=√(a+a) =2.23m/s?
tanθ=a？ /a？ =- 1.57
So the direction is arc tangent (-1.57)