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Dalton's partial pressure principle is applied to a college chemistry problem. Please refer to the supplementary question for details.
When the temperature drops to-10, the pressure in the container is only generated by air, and the volume of air at this time is 1L of the container volume.

1, find the partial pressure of air at 20 degrees.

P2 (air) V = n (air) RT2

P 1 (air) V = n (air) RT 1

1/ P2 = T 1/T2

P 1 (air) = P2(T 1/T2)

= 80.9 *(293 / 263)

= 90. 13 (kPa)

2. Find the partial pressure of water vapor at 20 degrees.

P total = P (aviation) +P(H2O)

P (H2O) =101.6-90.13 =1.47 9 kPa)

3. Find the mass of water vapor at 20 degrees.

H2O V =[m(H2O)/ 18]RT

m(H2O)= 1 1.47 * 1 * 18/8.3 14 * 293

= 0.085 (gram)