This is the first one.
The second force related to potential energy, such as gravity, electric field force and spring force, has nothing to do with path, but only with position. The work of these forces is equal to the product of force and displacement.
But when friction resistance and so on. Do reciprocating motion or curvilinear motion, work = force * distance.
How to forcibly find a job? For example, m= 1 and F=kt. Find the work done in 3 seconds and the work done in 3 meters?
If time changes
Calculate the average force during this period.
So the average force is the average of the initial force 0 and the final force.
So work = average force * displacement.
Displacement is calculated by accelerating motion.
M= 1, F=kt. Find the work done in 3 seconds and the work done in 3 meters? The average force is 1.5 Newton.
The total displacement in 3 seconds can be calculated, right?
Vt image area
Work completed within 3 meters
How long does it take to calculate the displacement of 3 meters?
Then calculate the output.
Half of the force at this time is the average force.
Work = average force * displacement
How to calculate how long the displacement of 3 meters is?
F=kt
Acceleration is the main factor.
The speed is quadratic.
What about the area?
Will the integral of velocity image be calculated?
can
The area enclosed by the X axis is 3, so the time can be calculated.
What if it's F=sint?
Similarly, velocity is the derivative of force.
Sint derivative = cost
Strive for speed.
The velocity derivative is the distance.
Speed is the derivative of force, so change it to v = cost.
The enclosed area can be integrated.
Can be exported twice.
Velocity image integration can also be
Just pay attention to the positive and negative when integrating.