One,

E (x) = e ((∑ xi)/10) =110 ∑ e (xi) =110 * (10 * 2. = 10)

d(x)= d((∑Xi)/ 10)= 1/ 100∑d(Xi)= 1/ 100 *( 10 * 6)= 3/3。

Second,

E (x1+x2) = e (x1)+e (x2) =1+2 = 3 (xi ~ x 2 (i) is my expectation).