The spherical shell is an equipotential body, so the potential at point P is equal to the potential at the outer surface of the spherical shell. Now find the potential of the outer surface of the spherical shell.

(1) Ask first? The electric field distribution outside the spherical shell is determined by Gauss theorem: E4 π r&; # 178; =Q/ε0 Therefore: e = q/4π ε 0r&; # 178;

(2) Re-integrating to find the external surface potential: u = ∫ edr = q/4π ε 0 ∫ dr/r&; # 178; =? -Q/4ω0r？ Substitute into the lower limit of integral? r2？ Upper limit? ∞? Get:

u = Q/4ω0r 2？

That is, the p-point field strength e? =0? Potential? u = Q/4ω0r 2

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