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How to find the radius of curvature in the second question of college physics? Ask the great god for a detailed explanation
The radius of curvature of this problem is 2v 2/3g under the root.

The vector decomposition of acceleration is combined with centripetal acceleration Company, and the specific method is as follows:

Extended data:

In differential geometry, the reciprocal of curvature is the radius of curvature, that is, r =1/K. The curvature of a plane curve is defined in differential terms of the rotation rate of the tangent direction angle to the arc length at a certain point on the curve, indicating the degree to which the curve deviates from the straight line. For a curve, it is equal to the radius of the arc closest to the curve at that point. For surfaces, the radius of curvature is the radius of the circle that is most suitable for the normal section or its combination.

The larger the radius of a circle, the smaller the degree of bending, and the closer it is to a straight line. So the larger the radius of curvature, the smaller the curvature, and vice versa.

If a circle with the same curvature can be found for a certain point on the curve, then the radius of curvature of that point on the curve is the radius of the circle (note that it is the radius of curvature of that point, and other points have other radii of curvature). It can also be understood as differentiating the curve as much as possible until it finally approaches an arc, and the radius corresponding to this arc is the radius of curvature at this point on the curve.

References:

Baidu encyclopedia-curvature radius