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Additional high score for detailed explanation of college physical optics.
The reflected light on the upper and lower surfaces of the film is coherent light. Because one of the reflected lights has a half-wave loss, the optical path difference =2ne+λ/2.

When the optical path difference is an integer multiple of the wavelength, the reflection is enhanced: 2ne+λ/2=kλ.

The wavelength of reflection enhancement λ=4ne/(2k- 1)

Let k =1:λ = 4ne = 4 * 5300 *1.33 = 4 * 6650+399 = 4 * 7049a infrared ray.

Let k=2:λ=4ne/3=4*7049/3=9399A infrared ray.

Let k=3:λ=4ne/5=4*7049/5=5639A visible light.

Let k=4:λ=4ne/7=4*7049/7=4028A Visible light let k = 5: λ = 4NE/5 = 4 * 7049/9 = 3133a Ultraviolet light.