As can be seen from the figure, n has two valence bond forms, one is -n =? According to the valence shell electron pair repulsion theory, N is a plane triangle configuration, and it is inferred that the hybridization type is sp2. The other is-NH-According to the valence shell electron pair repulsion theory, N is a triangular cone configuration, and it is inferred that the hybridization type is sp3.

Cu has 29 electrons arranged in 1s2? 2s2？ 2p6？ 3s2？ 3p6？ 3d 10？ 4s 1 (why not in 3d9? 4s2 is because it can ensure that the 3d track is full and the 4s track is half full. Valence electrons are outer electrons that participate in chemical reactions, that is, 3d 10? 4s 1 .

Observing the four N's around Cu, the upper left N and the lower right N were originally connected by H, and the number of bonds of N should still be 3 after bonding with Cu, so a covalent bond was formed with Cu. The left lower and right upper N used to have only one single bond and one double bond, but now they are bonded with Cu, which is caused by the coordination between the lone pair of N and Cu.

This question is a bit difficult in high school. Welcome to ask questions ~