Problem description:
An object with mass m is placed on a rough horizontal plane, and a horizontal pulling force F acts on the object, and the acceleration generated by the object is A. If the horizontal pulling force acting on the object becomes 2F, the acceleration generated by the object is 0.
()
A. between a and 2A, less than b equals c. Greater than 2A.
Analysis:
Let the friction force be f, the tension force be 2F, and the acceleration generated by the object be a.
According to Newton's second law
F-f=MA
f=F-MA
2F-f = horse
2F-(F-MA)=Ma
a=(F+MA)/M=F/M+A
Because (f-f)/m = a.
So F/M is greater than a.
Option d