= lim(x->； Infinite) (1+0)

= 1

Explanation: 1/x is infinitesimal, sinx is bounded function, and theorem: the product of bounded function and infinitesimal is infinitesimal.

2. The original formula = lim (x->; 0)[x/sinx*x+W]

= lim(x->； 0)[ 1*x+W]

=0+W

Description: Theorem: lim (x->; 0)x/sinx= 1，

W has no limit. W is the product of bounded function sin 1/x and infinite sin 1/sinx. There is no limit.

3. Original formula =0+ Bounded function without limit.