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Cixi City 20 1 1 The simulated mathematics test paper for junior high school graduates should be the one that Cixi City unified on May 6.
Reference answers and grading standards of mathematics test questions

First, multiple-choice questions (3 points for each small question, 36 points for * * *)

The title is123455678911112.

Answer B D D A C C A D C B

Fill in the blanks (3 points for each small question, *** 18 points)

Title:131415161718.

answer

(The answer is not unique)

36

③④

17 There are errors in the units in the problem diagram and the units in the problem. When correcting, the answer calculated by "time" is: calculated by "second", and the answer is 16200, but this answer has no practical significance. Both answers are correct when correcting.

Iii. Answering questions (***66 points)

Note: 1. Scoring is carried out in steps, and integral scores are set in each step;

2. If there are other solutions, as long as they are correct, you can refer to the grading standard and grade each step accordingly.

19. Solution:

= 2 points

= 3 points

= 4 points

When =3, =2, the original formula = 5 points.

20. Solution: The score is 1.

Get two points.

3 points

Get 4 points from ①.

Score 5 points from ②.

6 points

2 1. Solution: (1) The representative sample selected by Xiaoli is 1.

The average vision of the city's third-year graduates is 2 points.

(2) As shown in the figure (omitted), 5 points.

The median range is -7 points.

(3) The number of people whose eyesight meets the requirements = 1400 9 points.

22. Solution: (1) Let the analytical formula of parabola be 1.

The parabola passes through point C (3, 10)

3 points

4 points

(2) After translating the parabola downward by 4 units,

The analytical formula of parabola is:

Point D corresponding to point C is (3,6) 5 points.

Earn, get, get, 7 points.

PQ=5, 8 points

23. Solution: (1) (2) (3)

Note: the answer to each question is not unique, as long as it meets the conditions of the question.

Items (1) and (2) deserve 2 points, and item (3) deserves 3 points.

24. Solution: (1) Associated Original Currency

OA=OB,CA=CB

OC⊥AB 2 points

The straight line AB is tangent to ⊙ O at 4 points.

②o is OP⊥EF in p.

EP=FP 5 points

EF=2FG

FP=FG

EG⊥AB

FPO=∠FGA,

And ∠PFO=∠AFG.

△ OPF△ AGF 7 points

AF=FO=OC, which means AO=2OC.

∠A=

∠AOC=,∠AOB=

AB=,OC=6

9 points

25. Solution: (1) Suppose B needs days to complete this task alone, then A needs days to complete this task alone.

Judging from the meaning of the question: 2 points

Score for solving equation: 3 points

After testing, it is the root 4 of the equation.

5 points

A: It takes 80 days for Party A to complete the task alone, and 50 days for Party B to complete the task alone.

(2) The production days of enterprise B are 7 minutes.

(3) From the meaning of (2) and the question:

9 points

Solution:

Answer: Enterprise A must produce 10 points for at least 40 days.

26. Solution: (1)C(3,), m (0) 2 points (each 1 point).

BME is a right triangle.

The quadrilateral OABC is a diamond,

The straight line AC is three points of its symmetry axis.

PE⊥AC

Point p and point e, point o and point b are all symmetrical about AC by 4 points.

∠EBM=∠AOM=

BME is a right triangle with five angles.

(3) connect OE,

∠PBM =∠ EOM from symmetry

PBM= OAB Asia Pacific = AEO

∠EOM= OAB

∠EOM+∠EOA=

OAB +∠EOA=

Asia Pacific = AEO = 7 o'clock

B(3, 1)

OP= 1 so AP=4,

= 8 points

(4) As shown in Figure 2, the link OB is known from the question, meaning OP=OQ, POB= QOB,

OB⊥PQ,

OB⊥AC, pq∑AC can be known from the rhombic OABC of quadrilateral.

PE⊥AC

QPB=,

PQE is an isosceles triangle, which can only be PE=PQ 9.

The score comes from APE∽ AOB: PE=, 10.

Score from OPQ ∽ O AC: PQ= 1 1.

= Solution:

That is, when PQE is an isosceles triangle, 12 points.