Let the first even number be 2x, then the continuous even number is 2x+2, and 42 consists of n continuous even numbers.

1,.

When n =2,

2x + (2x + 2) = 42，

4x = 40，

2x = 20，2x +2 =22

So it is composed of two consecutive even numbers 20, 22 and 42.

2,

When n=3,

2x + (2x + 2) + (2x +4) = 42

6x + 6 =42

x =6

2x = 12

So it is composed of three consecutive even numbers 12, 14, 16.

3,

When n =4,

2x + (2x + 2) + (2x +4) + (2x + 6) = 42

8x + 12 =42，

8x =30

X = 3,75 (non-integer, rounded)

At this time, there is no continuous even synthesis 42.

4,

When n= 5,

2x+(2x+2)+(2x+4)+(2x+6)+(2x+8)= 42

10x + 20 =42，

X =2 2,2 (non-integer, rounded)

At this time, there is no continuous even synthesis 42.

5, when n=6,

2x+(2x+2)+(2x+4)+(2x+6)+(2x+8)+(2x+ 10)= 42

12x + 30 =42，

x = 1，

Then 2x = 2, 2x+2 =4, .......

So it is composed of six consecutive even numbers 2, 4, 6, 8, 10, 12.

Because 2x is an even number, the minimum value of 2x is 2, that is, the minimum value of x can only be 1 (that is, 2x >；; =2, x>= 1), so 42 can only consist of 6 consecutive even numbers at most.