The two power supplies are connected in series in reverse, and the current flows from the larger anode, so e1-E2 =15-12 = 3v is the real voltage of the power supply.

The two resistors are connected in series, and the total resistance is R =R 1+R2=30 kiloohms.

Current = total voltage divided by total resistance

Therefore, the current I = 3/30000 =110000 amp =0. 1 ma.

1 amp is equal to 1000 mA.

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