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Current location - Education and Training Encyclopedia - University ranking - University semicircle
University semicircle
1, a semicircle with a diameter of 8 cm:

2π×4÷2= 12.56 cm

2. Line segment length: 8 cm;

3. Length of peripheral large arc:

π×16× (135/360) =18.84 cm.

So the perimeter of the shaded part is:

12.56+8+ 18.84 = 39.4cm。

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