Considering the downward movement from the inclined plane, there is MGS in θ-f = Ma, where A is the acceleration of the center of mass, which is equal to the acceleration of the surface rolling, and F is the friction force;

Considering the rotation of the object, fr=Jα, α is the angular acceleration, and the magnitude is α = a/r, and j is the moment of inertia;

A = r 2 * mgsinθ/(r 2 * m+j) is obtained from the above formula.

So the smaller the moment of inertia, the earlier it reaches the lowest point.

Of the three objects, the smallest J is the ball, which is 2mr 2/5, so it ranks first.