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Answers to college physics experiments
It won't be long before you follow the calculation upstairs, plus the error.

10257.55 wrong value

The error value is calculated as follows: let Q= function f (x 1, x2, … xn), and xn is. According to the total differential formula dq = f1* dx1+F2 * dx2+...+FN * dxn, fn is the partial derivative of the nth independent influence factor at the standard point. The error can be represented by δ x, δ xn = sn, δ q = s, and d represents infinitesimal. When the δ value is small, δ can be approximately expressed as D. The general error is very small, so S = f1* s1+F2 * S2+...+fn * sn.

The two quantities with errors in this problem are square relations, and after derivation, they are quadratic relations. The derivative of the constant is 1, so the error is 0.0 1X2-0.05X2=-0.08.

So the answer is: 10257.55 0.08.