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A weak problem about lottery mathematics.
There is a combination of 132908 16 (33 * 32 * 31* 30 * 29 * 28)/(6 * 5 * 4 * 3 * 2 *1) * 65438.

There is only one first prize, so the probability of winning the first prize is11330,000.

I remember that the blue number of the two-color ball is 16.

So it should be117721088.

The combination of 6 out of 9 is

(9*8*7*6*5*4)/(6*5*4*3*2* 1)=84

The combination of 6 in 12 is

( 12* 1 1* 10*9*8*7)/(6*5*4*3*2* 1)=924

There is only one blue number.

So when 9+ 1 is selected, the probability of 6+ 1 is

117721088 * 84 =1/210965 (21million)

So when 12+ 1 is selected, the probability of 6+ 1 is

117721088 * 924 =119178 (less than 20000 points)

In fact, no matter how many groups you choose, it is the same.

When you choose 9+ 1, you should use 84*2= 168 yuan (equivalent to buying 84 bets).

Also select 12+ 1.

The first 33+ 16 is even worse.

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Lottery is also a kind of gambling, but it is allowed by the state.

And it is a shoo-in, because the "banker" draws too many people (about 5 1%).

You'll ask the first prize winner?

That's because he won 5 million, and the other 5 million people lost 2 yuan.

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I can't help but say that those posts about the skills of two-color ball (lottery) are deceptive (maybe not intentionally deceptive), because from a mathematical point of view, the probability of these numbers is the same, and they will never be affected by what happened in previous issues!

Unless someone cheats from it.