(2) The car lateral area given in the title is: S=LH=75m2.
The wind pressure corresponding to the maximum wind speed: p = vmax21.6 = 43.438+0.6n/m2.
Maximum thrust: f = PS = 43.221.6× 75n = 88292n.
(3) As shown in the figure
When the moment of F is greater than the moment of gravity, the car will capsize, so
Wind moment: MF=F? h2=88292×32N？ m= 132438N？ m
Gravity moment: MG=G? d2=2× 105× 1.52N？ m= 150000N？ m
MF < MG
The wind can't overturn the carriage.
Principle: To increase the gravity moment or decrease the thrust F moment, the feasible measures include: opening the windows on both sides of the train urgently, or moving the passengers on the train to the side where the strong wind blows.
Answer: (1) The quantitative relationship is: p = v 21.6;
(2) The maximum horizontal thrust of wind is 88292 N;
(3) The car will not roll over, so take feasible measures to open the windows on both sides of the train urgently, otherwise the passengers on the train will move to the side where the strong wind blows.