Special topics on college mathematical functions

1)f '(x)= 2(x+4)/√2+(2x+ 1)/√2 =[(4x+9)√2]/2(x > 0)

2) Parallel to 2y= 1 1x+3, the slope is 1 1/2, with [(4x+9) √ 2]/2 =1/2.

There is something wrong with the topic. The analytical formula of f(x) has been fixed, and there are no other parameters, so the image is fixed, and the abscissa is 1, so the coordinate point is fixed as (1, 15/√2), and the tangent of this point is fixed, and the tangent slope is [( 166].

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