EC = Eo+0.02963 log[Cu2+]= 0.337+0.02963 log 1 = 0.337V

Negative electrode = positive electrode half cell reaction: 2h++2e-> H2( 1 atm)

ea = Eo+0.05926 log[H+]=-0.05926 ph

The electromotive force of the battery = EC-EA = 0.337+0.05926 pH = 0.48 V.

Therefore, pH=2.4 1.

-

0.52 1 V is Cu++e->; Electrode potential of copper.