When the rotating shaft is a cylindrical shaft, I = Mr 2/2.

In ...

m

Is the mass of the cylinder, r

Is the radius of the cylinder.

For a particle I = Mr 2, where

m

It's its mass, R.

Is the vertical distance between the particle and the axis of rotation.

The moment of inertia only depends on the shape, mass distribution and the position of the rotation axis of the rigid body, and has nothing to do with the state of the rigid body rotating around the axis (such as the magnitude of angular velocity).

For a homogeneous rigid body with regular shape, it can be calculated by integral. Generally, a calculated formula is brought in. For irregular rigid bodies or uneven rigid bodies, the moment of inertia is generally measured by experimental methods.

For a cylinder, a hollow cylinder with radius r, thickness dr and height l is taken as the research object, its mass dm=ρ*2πr*L*dr, and its moment of inertia di = r 2 * ρ * 2π r * l * dr By integrating di from 0 to r, I =1/2π r4 * l.

This I am ai.

Watch me type hard. Give me a good evaluation, dear.