This is the summation formula of indefinite integral, which can be disassembled.

In addition, ∫( 1-sin? x)dx

=∫ 1dx-∫sin？ xdx

=x-∫sin？ xdx

How about ∫sin xdx=∫sin？ x*sinxdx

=-∫( 1-cos？ x)/2d(cosx)

=-∫d(cosx)+∫cos？ xd(cosx)

=-cosx+ 1/3*cos？ x+c

Comprehensive ∫( 1-sin? x)dx=x-cosx+ 1/3*cos？ x+c

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