If the solution is diluted, the mass of solute will not change before and after the reaction; Take 98% sulfuric acid 10 ml (density 1.84g/cm3) to prepare 10% sulfuric acid solution. How many grams of water do you need?

Analysis: The calculation principle of this problem is that the mass of solute in solution remains unchanged before and after dilution.

The specific solution is as follows: the mass of 10ml sulfuric acid solution is10×1.84 =18.4g, in which the mass of solute is18.4× 98% =18.032g.

Therefore, the mass of 10% sulfuric acid solution is:18.032/10% =180.32g, in which the water content is:180.32-18.032 =/. So the added water is obtained by subtracting the water in the original sulfuric acid:162.288-0.368 =161.92g.

Answer:161.92g.