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The answer to the eighth question on page 1 12 of the seventh grade mathematics textbook for compulsory education.
The sum of the ages of the father and the woman is 9 1. When the father is twice as old as the woman, the woman's age is 1/3 of the father's age. Find out the daughter's age.

The age gap between father and daughter is constant.

According to "when the father's age is twice that of the daughter, the daughter's age is one third of the father's age."

The age gap is:

Father's current age-female's current age = twice of female's current age (father's current age)-father's current age 1/3 (female's current age)

So the father's present age × (1+ 1/3) = the woman's present age ×3.

That is, father's age =9/4 daughter's age.

So: My daughter is: 9 1÷( 1+9/4)=28 (years old) this year.

Father's age is: 9 1-28 = 63.

I hope I can help you!