(2)① On the autosome, reed flower BB× non-reed flower bb→Bb (reed flower). F 1 free mating, then Bb×Bb→ 1BB, 2Bb, 1BB. If the phenotype of F2 is Luhua: Non-Luhua =3: 1, it is located on the autosome.
② Located on the sex chromosome, it is a homologous fragment of ZW. Therefore, female cock zwb× non-grandfather chicken ZbZb→ZBZb (Lu Hua grandfather chicken), ZBB× ZWB →1ZBB,1ZBB,1ZBB. There are no non-reed female chickens in the offspring. therefore ...
(Sorry, the answer was wrong before, and I didn't see the homologous segment ...............)