Then the pressure caused by the surface tension of the liquid is PS = pg △ H.
Let the capillary radius be R, the liquid Zhang Liwei δ,
The internal pressure of hemispherical bubble is: P=2δ/r, which is the same as Ps, that is, p = pg δ h.
The static pressure is pgh.
The pressure required to blow out hemispherical bubbles is:
Static pressure+bubble internal pressure+pressure caused by surface tension = pgh+p+PS = pgh+2pg △ h.
It's too long to finish learning, for reference only. The initial answer forgot the static pressure.