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Solutions to college physics thinking questions
1, the absolute error is certain, the greater the n, the smaller the relative error and the more accurate the measurement. 2. When M2 is strictly perpendicular to M 1, that is, M2ˊ is strictly parallel to M 1, the interference obtained is isoclinic interference. Interference fringes are concentric rings of light and dark located at infinity or on the focal plane of a lens. The characteristics of interference ring are: sparse inside and dense outside According to the theory of equal inclination interference, when the distance d between M 1 and M2' decreases, the radius of any designated K-level fringe will decrease and gradually shrink and disappear at the center, that is, the fringe will "sink"; When d increases, that is, the stripes are "exposed", the greater the thickness of M 1 and m2', the smaller the distance between adjacent bright (or dark) stripes, that is, the denser the stripes, the more difficult it is to identify. Whenever a ring "sinks" or "pops up", D correspondingly increases or decreases the distance of λ/2. If the number of "trap" rings or "exit" rings is n and the change of d is δD, then δD = N *λ/2.

Then: λ = 2 δ d/n

If δ d and n are known, λ can be calculated. 3. According to the theory of isoclinic interference, when the distance d between M 1 and M2' decreases, the radius of any designated K-level fringe will decrease, and gradually shrink and disappear at the center, that is, the fringe will "sink in" (is this what you call "grey annihilation"? ); When d increases, the stripes are "used up". When M2 moves from left to right, "null return error" will appear. Therefore, after stopping at a certain position, there may be stripes or annihilation due to "empty return error".