This is the first chapter.
The seventh grade mathematics (second) the first chapter "Algebraic expression operation" examination questions.
I. Fill in the blanks (3 ′× 9)
1、3-2=____;
2. There is a monomial with a coefficient of 2 and a degree of 3. This single item may be _ _ _ _ _ _ _;
3、a = a3
4. An electronic computer can do 108 calculations per second, and it can do _ _ operations in 8 minutes by scientific notation;
5. A ten digit is A, the unit mathematics is B, and the two digits are expressed as10A+B. If you exchange this two digit with a one digit, you get a new two digit, which is _ _ _ _ _ _ _ _, and the difference between these two digits is _ _ _ _ _ _ _ _ _;
6. There is a calculation problem: (-A4) 2. Teacher Li found that the whole class has the following four solutions.
①(-a4)2 =(-a4)(-a4)= a4 a4 = A8;
②(-a4)2 =-a4×2 =-A8;
③(-a4)2 =(-a)4×2 =(-a)8 = A8;
④(-a4)2 =(- 1×a4)2 =(- 1)2(a4)2 = A8;
What you think is completely correct is (fill in the serial number) _ _ _ _ _ _ _;
7,3m = 6 and 3n=2, then 3m+n=
8. There are two rectangular pieces of paper (as shown in Figure (2)). Fold them into the shape of Figure (3), and the graphic area is _ _ _ _ _ _ _ _ _;
Answer
b b
Figure (2) Figure (3)
9. Xiaohua puts the edge of a square paper with a side length of one centimeter (as shown in Figure 4) at 1 cm.
After the length is reduced by 1 cm, a square piece of paper is obtained, which is
The area is _ _ _ _ _ cm;
Second, multiple-choice questions (3 ′× 3)
10, the following operation is correct ()
a、a5 a5=a25 B、a5+a5=a 10
c、a5 a5=a 10 D、a5 a3=a 15
1 1, and the result of calculating (-2a2) 2 is ().
a、2a4 B 、-2a4 C、4a4 D 、-4a4
12, the result of expressing 3× 10-2 by decimal is ()
a 、-0.03 B 、-0.003 C、0.03 D、0.003
Iii. Calculate the following problem (8 ′× 5)
13 、( 2a+ 1)2-(2a+ 1)(- 1+2a) 14 、( 3xy2) (-2xy)
15 、( 2a6x3-9ax5)÷(3ax3) 16 、(-8a4b5c÷4ab5) (3a3b2)
17 、( x-2)(x+2)-(x+ 1)(x-3)
Fourth, (5') Xiaoying, a seventh-grade student, is a thoughtful and helpful classmate. One day, Xiaoming, a neighbor's pupil, asked Xiaoying's sister to help him check his homework:
7×9= 63 8×8=64
1 1× 13= 143 12× 12= 144
23×24=624 25×25=625
After Xiaoying carefully checked, he praised Xiaoming for being smart and careful, and his homework was all right! Xiaoying also found a rule from these problems. Do you know what patterns Xiaoying found? Please indicate this rule in letters and explain its correctness.
In a flood, about 2.5× 105 people were homeless. If a tent covers an area of 100 m2, 40 beds can be put (each bed sleeps 1 person). How many tents are needed to accommodate all the homeless people? About how much space do these accounts take up? How many people can be put in the classroom of your school? About how many such classrooms are needed to accommodate these people?
6.(6') As shown in the figure below, there are several rectangles or squares. Use them to spell out a new rectangle or square (each one is used) and calculate its area.
business English
A b
7. Xiaohua watched a dance program on TV: seven dancers in different national costumes changed queues in front of the audience. He was lost in thought: how many queue changes will these seven actors have in front of the audience? ..... In order to solve this problem, he thought and explored like this:
(1) If there is only one actor A, there is only queue transition A, totaling 1 species;
(2) If there are two actors A and B, there will be a queue change: AB and BA, a total of two;
(3) If there are three actors A, B and C, there will be a queue change: ABC, ACB, BAC, BCA, CAB, CBA, a total of six kinds;
(4) If there are four actors, A, B, C and D, there will be a queue change (Xiaohua writes these four letters in order on paper) ... Count them, wow! There are 24 kinds. It changes so fast. What about five, six or seven actors? It seems that we can't storm any more, otherwise we will ... or we'd better outsmart ourselves. ...
Apply the table again. I remember there is such an example in the book, which the teacher has demonstrated. It can more clearly reflect the law of numbers:
Number of actors _1_ 2 _ 3 _ 4 _ ...
Possible number of transformations _ 1 _ 2 _ 6 _ 24 _..._
……
(1) Do you know how many queues these five dancers will have in front of the audience? Tell me your reasons.
(2) Please carefully understand Xiaohua's problem-solving strategy, and then explore how many queue changes N dancers have in front of the audience. State your reasons.
The seventh grade mathematics (second) the first chapter "Algebraic expression operation" examination questions.
I. Fill in the blanks (3 ′× 9)
1、3-2=____;
2. There is a monomial with a coefficient of 2 and a degree of 3. This single item may be _ _ _ _ _ _ _;
3、a = a3
4. An electronic computer can calculate 108 times per second, which can be expressed in 8 minutes by scientific notation.
Do _ _ _ _ _ times;
5. A ten digit is A, a one digit is B, and a two digit is10A+B. If the ten digit and the one digit of this two digit are exchanged, a new two digit is _ _ _ _ _, and the difference between these two digits is _ _ _ _ _ _;
6. There is a calculation problem: (-A4) 2. Teacher Li found that the whole class has the following four solutions.
①(-a4)2 =(-a4)(-a4)= a4 a4 = A8;
②(-a4)2 =-a4×2 =-A8;
③(-a4)2 =(-a)4×2 =(-a)8 = A8;
④(-a4)2 =(- 1×a4)2 =(- 1)2(a4)2 = A8;
What you think is completely correct is (fill in the serial number) _ _ _ _ _ _ _;
7. In his book The Origin of Prescription, Jia Xian, a mathematician of the Northern Song Dynasty in China, has the following diagram. Through observation, do you think that A = _ _ _ _ _ _ _
8. There are two rectangular pieces of paper (as shown in Figure (2)). Fold them into the shape of Figure (3), and the graphic area is _ _ _ _ _ _ _ _ _;
9. Xiaohua reduces the side length of a square paper with a side length of one centimeter (as shown in Figure 4) by 1 cm, and then gets a square paper again. At this time, the area of the paper is _ _ _ _ _ cm;
Second, multiple-choice questions (3 ′× 3)
10, the following operation is correct ()
a a5 a5 = a25 B a5+a5 = a 10 C a5 a5 = a 10D a5 a3 = a 15
1 1, the result of calculating (-2a2) 2 is () a2a4b-2a4c4a4d-4a4.
12, the result of expressing 3× 10-2 by decimal is ()
A -0.03 B -0.003 C 0.03 D 0.003
Iii. Calculate the following problem (8 ′× 5)
13 、( 2a+ 1)2-(2a+ 1)(- 1+2a) 14 、( 3xy2) (-2xy)
15 、( 2a6x3-9ax5)÷(3ax3) 16 、(-8a4b5c÷4ab5) (3a3b2)
17 、( x-2)(x+2)-(x+ 1)(x-3)
Fourth, (6') Xiaoying, a seventh-grade student, is a thoughtful and helpful classmate. One day, Xiaoming, a neighbor's pupil, asked Xiaoying's sister to help him check his homework:
7×9= 63 8×8=64
1 1× 13= 143 12× 12= 144
23×24=624 25×25=625
After Xiaoying carefully checked, he praised Xiaoming for being smart and careful, and his homework was all right! Xiaoying also found a rule from these problems. Do you know what patterns Xiaoying found? Please indicate this rule in letters and explain its correctness.
5.(7') As the ancients said, everything must be judged first. You must think clearly before you do anything, so as not to be blind. One day, Xiaohua needs to calculate the area of an L-shaped flower bed. Before starting the measurement, Xiao Ming drew the following schematic diagram according to the shape of the flower bed, and marked the side length to be measured with letters (as shown in the figure). When calculating the area with a column chart, Xiao Ming found that it was necessary to measure the length of the other side. Where do you think he needs to measure? Please mark it in the picture and indicate it with the letter n, and then find out its area.
(6') As shown in the figure, there are several rectangular or square cards. Please use these cards to form a rectangle or square.
Requirements: each type of card in the puzzle must be available, and the cards cannot overlap.
Draw a schematic diagram and calculate its area.
7. Xiaohua watched a dance program on TV: seven dancers in different national costumes changed queues in front of the audience. He was lost in thought: how many queue changes will these seven actors have in front of the audience? ..... In order to solve this problem, he thought and explored like this:
(1) If there is only one actor A, there is only queue transition A, totaling 1 species;
(2) If there are two actors A and B, there will be a queue change: AB and BA, a total of two;
(3) If there are three actors A, B and C, there will be a queue change: ABC, ACB, BAC, BCA, CAB, CBA, a total of six kinds;
(4) If there are four actors, A, B, C and D, there will be a queue change (Xiaohua writes these four letters in order on paper) ... Count them, wow! There are 24 kinds. It changes so fast. What about five, six or seven actors? It seems that we can't storm any more, otherwise we will ... or we'd better outsmart ourselves. ...
Apply the table again. I remember there is such an example in the book, which the teacher has demonstrated. It can more clearly reflect the law of numbers:
Number of actors _1_ 2 _ 3 _ 4 _ ...
Possible number of transformations _ 1 _ 2 _ 6 _ 24 _..._
……
(1) Do you know how many queues these seven dancers will have in front of the audience? Tell me your reasons.
(2) Please carefully understand Xiaohua's problem-solving strategy before exploring: What is the last digit of 220? Tell me what you think. For example, the last digit of 25 is 5; The last digit of 2043 is 3.
People's education printing plate seventh grade fifth volume unit examination questions
I. Fill in the blanks (30 points)
(1) If 0 < α < 90, the complementary angle of 90-α is a, and the angle is 90 +a A.
(2) As shown in the following figure (1), ∠ 1=∠5, then ∠3 = ∠7, ∠4 = ∠6, ∠ 1+∞.
(3) As shown in the following figure (2), ∠ 2 = ∠ 3, ∠ 1 = 62 24', then ∠ 4 = 62.4.
(4) As shown in the following figure (3), if ∠ 1 is equal to the remaining angles, and ∠2 is equal to three times the remaining angles, then l 1 and the position of l2.
The relationship is parallel.
(5) As shown in Figure (4), FA is the bisector of ∠CFE. If ∠ 1 = 40, ∠ 2 = 70 ∠ EFB = 1 10.
( 1) (2) (3) (4)
(6) The proposition that the complementary angles of the same angle are equal is a true proposition, and it is written in the form of "If …… then ………"
If two angles are complementary angles of the same angle
Then they are equal.
(7) If the line segment PO and the line segment AB are perpendicular to each other, and the point O is between A and B, let the distance from P to AB be m,
The distance from p to a is n, so the relationship between m and n is m.
(8)C is the midpoint of line AB, D is a point on line CA, and E is
The midpoint of the AD line, if BD=6, EC= 3.
(9) As shown in the following figure, OA⊥OB,∠AOD= ∠COD, ∠BOC=3∠AOD,
Then the degree of ∠COD is 30.
Second, multiple-choice questions (18 points)
1. Among the following propositions, the pseudo-proposition is (d)
A. If you cross a point, you can make a straight line perpendicular to the known straight line.
If a straight line is perpendicular to one of the two parallel lines, it must be perpendicular to the other.
C two lines parallel to the same line are parallel.
D. Two lines perpendicular to the same line are vertical.
2. Of the two complementary angles, two times of one angle is smaller than three times of the other angle 10, and these two angles are (b).
A. 104,66 B. 106,74 C. 108,76 D. 1 10,70
3. As shown in the figure below, AB‖CD‖EF, and AF‖CG. The angle (not counting itself) equal to ∠A in the figure has (b).
A.5 B.4
C.3 D.2
4. Given a straight line l 1, l2 and l3 are on the same plane. If l 1⊥l2 and l2‖l3, the positional relationship between l 1 and l3 is (c).
A. Parallel B. Intersecting C. Vertical D. None of the above is correct.
5. If the two sides of ∠A and ∠B are parallel, then the relationship between ∠A and ∠B is (D).
A.b. Complementarity or complementarity
C.d. Equality or Complementarity
6. As shown in the figure below, point E is on the extension line of BC, and it cannot be judged that AB‖CD is (A) under the following conditions.
A.∠3=∠4 B.∠ 1=∠2
C.∠B =∠DCE D∠D+∠DAB = 180
Iii. Judgment (18)
The complementary angles of (1) vertex angles are equal. (right)
(2) The bisectors of adjacent complementary angles are perpendicular to each other. (right)
(3) Only one vertical line can be drawn on the plane. (error)
(4) Two straight lines that do not intersect in the same plane are called parallel lines. (right)
(5) If a straight line is perpendicular to one of the two parallel lines,
Then this straight line is perpendicular to another straight line among the parallel lines. (right)
(6) Two straight lines are cut by a third straight line, and the sum of two pairs of internal angles on the same side is equal to a fillet. (right)
(7) The distance from a point to a straight line is the length of the perpendicular from this point to this straight line. (error)
(8) Axiomatization: One and only one straight line is parallel to the known straight line and intersects a point outside the straight line. (right)
(9) The vertical section from a point outside a straight line to this straight line is called the distance from this point to this straight line. (error)
Four, answer questions (54 points)
1. As shown in the following figure, EO⊥AB is in O, and the straight line CD passes through O, ∠ EOD: ∠ EOB = 1: 3, and find the degrees of ∠AOC and ∠AOE.
Solution: let EOD angle be X.
3x = 90°
X=30
DOB = 90-30 = 60。
Because: angle DOB= angle AOC (equal to vertex angle)
So: angle AOC=60.
Because: AB is a straight line (known)
So: angle AOB = 180.
Because: angle AOE= angle AOB- angle EOB
So: AOE = 180-90.
=90
Answer: AOE=90, AOC=60.
2. Given that the difference between two complementary angles is equal to 40 30 ˊ, find the complementary angle of the smaller angle.
Solution: Let the larger angle be x 。
X-( 180-x)=40.5
x- 180+x=40.5
X+X =40.5+ 180
2X=220.5
X= 1 10.25
The smaller angle is:180-110.25 = 69.75.
The complementary angle of the smaller angle is: 90-69.75 = 20.25.
A: The complementary angle of the smaller angle is 20.25.
3. As shown in the figure, AB‖CD, ∠ 1=∠2, ∠3=∠4, find the degree of ∠FPE.
Solution:
AB | | CD (known)
∴ (∠ 3+∠ 4)+(∠1+∠ 2) =180 (two straight lines are parallel and the internal angles on the same side are complementary).
∠∠ 1 =∠2, ∠3=∠4 (known)
∴ 2 ∠ 3+2 ∠ 1 = 180 (equivalent substitution)
∴2(∠ 1+∠3)= 180
∴∠ 1+∠3=90
∠∠3 =∠4 (known)
∴∠ 1+∠ 4 = 90 (equivalent substitution)
The sum of the internal angles of a triangle is 180.
∴∠p= 180 -∠ 1-∠4
= 180 -(∠ 1+∠4)
= 180 -90
=90
A: FPE equals 90 degrees.
4. As shown in the figure, find out at least five problems that can make AD‖BC hold.
Solution: (1)≈ 1 =≈2
(2) ∠ADC+∠DCB= 180
(3)4 =∠GBC
(4)5+∠GBC = 180
(5)3 =∠ADC
5. Draw as required:
(1) Draw a vertical line of lines m and n through point p as shown in figure (1).
(2) As shown in Figure (2), draw the vertical line PB of OA through point P and intersect with OC at point B; Draw a vertical line segment PD from point P to OC;
Then PD, < or = symbol); The reason is that the vertical segment is the shortest.
(3) After translation, the vertex B of △ABC has moved to point E, please translate the △DEF.
Figure (1) Figure (2) Figure (3)
6. As shown in the figure, it is known that AB ‖ de, ∠ ABC = 80, ∠ CDE = 140, and the number of times to find ∠BCD.
Solution: As shown in figure 1:
Do pk parallel to ab.
∫∠ABC = 80 (known)
∴∠BCP= 180 -80 = 100
(The complementary angles of two parallel lines which are internal angles to each other)
∫∠CDE = 140 (known)
∴∠DCK= 180 - 140 =40
(The complementary angles of two parallel lines which are internal angles to each other)
∫∠PCK = 180 (angle definition)
∴∠BCD= 180 - 100 -40
=40
Answer: ∠ BCD = 40. (Figure 1)
Answer:
First, fill in the blanks:
⑴α,90 +α; ⑵=,=, 180 ; ⑶62 42′; (4) parallel to each other; ⑸ 70 , 1 10 ; [6] True, two angles are complementary angles of the same angle, and the two angles are equal; ⑺m<; n; ⑻ 3 ; ⑼ 30 .
Second, multiple choice questions
1.d; 2.b; 3.b; 4.c; 5.d; 6 A。
Third, the judgment question
⑴√; ⑵√; ⑶╳; ⑷√; ⑸√; ⑹√; ⑺╳; ⑻√; ⑼╳.
Fourth, answer questions:
1.∠AOC=60,∠AOE = 90; 2.20 15′; 3.90 ;
4.①∠ 1=∠2; ②∠4 =∠GBC; ③∠3 =∠ADC; ④∠5+∠GBC = 180⑤∠ADC+∠DCB = 180⑥AD‖EF,BC‖EF
5.( 1) omitted; ⑵& lt; The vertical segment is the shortest; Sketch (3) The sketch is 6. 40.
Paste it into Word by yourself.
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